我准备使用 JPA 2.0 的 CriteriaBuilder API 实现如下SQL查询语句:
我的Java代码大致如下:
不幸的是,执行上述代码,结果却抛出如下异常:
Caused by: org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected token: in near line 1, column 154 [select generatedAlias0 from org.lesson001.www.bean.Emp as generatedAlias0 where ( generatedAlias0.dept.id=1 ) and ( generatedAlias0.groupId in (1, 3, 5) in (null) )]
at org.hibernate.hql.internal.ast.QuerySyntaxException.convert(QuerySyntaxException.java:74)
at org.hibernate.hql.internal.ast.ErrorTracker.throwQueryException(ErrorTracker.java:93)
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.parse(QueryTranslatorImpl.java:301)
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:189)
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:144)
at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:113)
at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:73)
at org.hibernate.engine.query.spi.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:162)
at org.hibernate.internal.AbstractSharedSessionContract.getQueryPlan(AbstractSharedSessionContract.java:604)
at org.hibernate.internal.AbstractSharedSessionContract.createQuery(AbstractSharedSessionContract.java:716)
请问,在Hibernate中,如何使用 JPA CriteriaBuilder 实现 IN 查询呢?
对了,我使用的是当前最新的 Hibernate 5.4.22.Final。